What are the solutions to the equation 7m^2+2m=6 ?

The solutions to the equation 7m^2+2m=6 are m=(-1+sqrt(43))/7 ,m=-(1+sqrt(43))/7

Find the zeros of 7m^2+2m=6

The zeros of 7m^2+2m=6 are m=(-1+sqrt(43))/7 ,m=-(1+sqrt(43))/7

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7 m^{2} + 2 m = 6

m = \frac{- 1 + 43}{7}, m = - \frac{1 + 43}{7}

Decimal

m = 0.79391 \dots, m = - 1.07963 \dots

Solution steps

7 m^{2} + 2 m = 6

Move

6

to the left side

7 m^{2} + 2 m - 6 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 7 ( - 6 )}{2 \cdot 7}

2^{2} - 4 \cdot 7 (- 6) = 243

m_{1, 2} = \frac{- 2 \pm 2 43}{2 \cdot 7}

Separate the solutions

m_{1} = \frac{- 2 + 2 43}{2 \cdot 7}, m_{2} = \frac{- 2 - 2 43}{2 \cdot 7}

m = \frac{- 2 + 2 43}{2 \cdot 7} : \frac{- 1 + 43}{7}

m = \frac{- 2 - 2 43}{2 \cdot 7} : - \frac{1 + 43}{7}

The solutions to the quadratic equation are:

m = \frac{- 1 + 43}{7}, m = - \frac{1 + 43}{7}

x^{2} + 8 x + 19 = 8

3 (x - 2)^{2} (x + 5) = 3 (x - 1)^{2} (x - 1) + 3

(k - 2) x^{2} - 5 x + 2 k = 0

(3 x - 1)^{2} = 4

(3 x - 1)^{2} = 7

What are the solutions to the equation 7m^2+2m=6 ?
The solutions to the equation 7m^2+2m=6 are m=(-1+sqrt(43))/7 ,m=-(1+sqrt(43))/7
Find the zeros of 7m^2+2m=6
The zeros of 7m^2+2m=6 are m=(-1+sqrt(43))/7 ,m=-(1+sqrt(43))/7