What are the solutions to the equation m^2+4m+20=0 ?

The solutions to the equation m^2+4m+20=0 are m=-2+4i,m=-2-4i

Find the zeros of m^2+4m+20=0

The zeros of m^2+4m+20=0 are m=-2+4i,m=-2-4i

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m^{2} + 4 m + 20 = 0

m = - 2 + 4 i, m = - 2 - 4 i

Solution steps

m^{2} + 4 m + 20 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 20 : 8 i

m_{1, 2} = \frac{- 4 \pm 8 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 4 + 8 i}{2 \cdot 1}, m_{2} = \frac{- 4 - 8 i}{2 \cdot 1}

m = \frac{- 4 + 8 i}{2 \cdot 1} : - 2 + 4 i

m = \frac{- 4 - 8 i}{2 \cdot 1} : - 2 - 4 i

The solutions to the quadratic equation are:

m = - 2 + 4 i, m = - 2 - 4 i

2 = y^{2}

3 x (5 x - 6) = 4 - 2 x

(0 - 2)^{2} + (y + 3)^{2} = 9

2 x^{2} + 16 x + 4 = 0

a^{2} + 7 a + 2 = 0

What are the solutions to the equation m^2+4m+20=0 ?
The solutions to the equation m^2+4m+20=0 are m=-2+4i,m=-2-4i
Find the zeros of m^2+4m+20=0
The zeros of m^2+4m+20=0 are m=-2+4i,m=-2-4i