What are the solutions to the equation 3w^2+w-9=0 ?

The solutions to the equation 3w^2+w-9=0 are w=(-1+sqrt(109))/6 ,w=(-1-sqrt(109))/6

Find the zeros of 3w^2+w-9=0

The zeros of 3w^2+w-9=0 are w=(-1+sqrt(109))/6 ,w=(-1-sqrt(109))/6

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3 w^{2} + w - 9 = 0

w = \frac{- 1 + 109}{6}, w = \frac{- 1 - 109}{6}

Decimal Notation

w = 1.57338 \dots, w = - 1.90671 \dots

Solution steps

3 w^{2} + w - 9 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

1^{2} - 4 \cdot 3 (- 9) = 109

w_{1, 2} = \frac{- 1 \pm 109}{2 \cdot 3}

Separate the solutions

w_{1} = \frac{- 1 + 109}{2 \cdot 3}, w_{2} = \frac{- 1 - 109}{2 \cdot 3}

w = \frac{- 1 + 109}{2 \cdot 3} : \frac{- 1 + 109}{6}

w = \frac{- 1 - 109}{2 \cdot 3} : \frac{- 1 - 109}{6}

The solutions to the quadratic equation are:

w = \frac{- 1 + 109}{6}, w = \frac{- 1 - 109}{6}

k, k^{2} + \frac{R}{L} k + \frac{1}{L C} = 0

c^{2} - 14 = 11

a^{2} - 6 a + 10 = 0

36.75 = (30 - x)^{2} \cdot 0.5

3 x^{2} - 12 x + 2

What are the solutions to the equation 3w^2+w-9=0 ?
The solutions to the equation 3w^2+w-9=0 are w=(-1+sqrt(109))/6 ,w=(-1-sqrt(109))/6
Find the zeros of 3w^2+w-9=0
The zeros of 3w^2+w-9=0 are w=(-1+sqrt(109))/6 ,w=(-1-sqrt(109))/6