What are the solutions to the equation a^2-6a+10=0 ?

The solutions to the equation a^2-6a+10=0 are a=3+i,a=3-i

Find the zeros of a^2-6a+10=0

The zeros of a^2-6a+10=0 are a=3+i,a=3-i

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a^{2} - 6 a + 10 = 0

a = 3 + i, a = 3 - i

Solution steps

a^{2} - 6 a + 10 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 10 : 2 i

a_{1, 2} = \frac{- ( - 6 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 6 ) + 2 i}{2 \cdot 1}, a_{2} = \frac{- ( - 6 ) - 2 i}{2 \cdot 1}

a = \frac{- ( - 6 ) + 2 i}{2 \cdot 1} : 3 + i

a = \frac{- ( - 6 ) - 2 i}{2 \cdot 1} : 3 - i

The solutions to the quadratic equation are:

a = 3 + i, a = 3 - i

36.75 = (30 - x)^{2} \cdot 0.5

3 x^{2} - 12 x + 2

2 (x - 16) = (x - 8) (x + 2)

5 x^{2} - 2 x - 8 = 0

\frac{x ( x - 3 )}{2} = 54

What are the solutions to the equation a^2-6a+10=0 ?
The solutions to the equation a^2-6a+10=0 are a=3+i,a=3-i
Find the zeros of a^2-6a+10=0
The zeros of a^2-6a+10=0 are a=3+i,a=3-i