What are the solutions to the equation (x-2)^2=27 ?

The solutions to the equation (x-2)^2=27 are x=3sqrt(3)+2,x=-3sqrt(3)+2

Find the zeros of (x-2)^2=27

The zeros of (x-2)^2=27 are x=3sqrt(3)+2,x=-3sqrt(3)+2

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(x - 2)^{2} = 27

x = 33 + 2, x = - 33 + 2

Decimal Notation

x = 7.19615 \dots, x = - 3.19615 \dots

Solution steps

(x - 2)^{2} = 27

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 27 : x = 33 + 2

Solve

x - 2 = - 27 : x = - 33 + 2

The solutions to the quadratic equation are:

x = 33 + 2, x = - 33 + 2

k^{2} - k - 30 = 0

1 5^{2} = x^{2} + 1 2^{2}

x^{2} + 2 x - (m^{2} - 1) = 0

1 = e^{2}

t^{2} - 3 t - 28 = 0

What are the solutions to the equation (x-2)^2=27 ?
The solutions to the equation (x-2)^2=27 are x=3sqrt(3)+2,x=-3sqrt(3)+2
Find the zeros of (x-2)^2=27
The zeros of (x-2)^2=27 are x=3sqrt(3)+2,x=-3sqrt(3)+2