What are the solutions to the equation x^2+2x-(m^2-1)=0 ?

The solutions to the equation x^2+2x-(m^2-1)=0 are x=-m-1,x=m-1

Find the zeros of x^2+2x-(m^2-1)=0

The zeros of x^2+2x-(m^2-1)=0 are x=-m-1,x=m-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 2 x - (m^{2} - 1) = 0

x = - m - 1, x = m - 1

Solution steps

x^{2} + 2 x - (m^{2} - 1) = 0

Expand

x^{2} + 2 x - (m^{2} - 1) : x^{2} + 2 x - m^{2} + 1

x^{2} + 2 x - m^{2} + 1 = 0

Factor

x^{2} + 2 x - m^{2} + 1 : (x + m + 1) (x - m + 1)

(x + m + 1) (x - m + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + m + 1 = 0 or x - m + 1 = 0

Solve

x + m + 1 = 0 : x = - m - 1

Solve

x - m + 1 = 0 : x = m - 1

The solutions to the quadratic equation are:

x = - m - 1, x = m - 1

1 = e^{2}

t^{2} - 3 t - 28 = 0

(2 x - 1)^{2} + 1 = 26

4 y^{2} = 9

10 x^{2} + 260 x - 23800 = 0

What are the solutions to the equation x^2+2x-(m^2-1)=0 ?
The solutions to the equation x^2+2x-(m^2-1)=0 are x=-m-1,x=m-1
Find the zeros of x^2+2x-(m^2-1)=0
The zeros of x^2+2x-(m^2-1)=0 are x=-m-1,x=m-1