What are the solutions to the equation (-1)/6 x^2+x-3=0 ?

The solutions to the equation (-1)/6 x^2+x-3=0 are x=3-3i,x=3+3i

Find the zeros of (-1)/6 x^2+x-3=0

The zeros of (-1)/6 x^2+x-3=0 are x=3-3i,x=3+3i

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\frac{- 1}{6} x^{2} + x - 3 = 0

x = 3 - 3 i, x = 3 + 3 i

Solution steps

\frac{- 1}{6} x^{2} + x - 3 = 0

Multiply both sides by

6

- x^{2} + 6 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) ( - 18 )}{2 ( - 1 )}

Simplify

6^{2} - 4 (- 1) (- 18) : 6 i

x_{1, 2} = \frac{- 6 \pm 6 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 6 i}{2 ( - 1 )}, x_{2} = \frac{- 6 - 6 i}{2 ( - 1 )}

x = \frac{- 6 + 6 i}{2 ( - 1 )} : 3 - 3 i

x = \frac{- 6 - 6 i}{2 ( - 1 )} : 3 + 3 i

The solutions to the quadratic equation are:

x = 3 - 3 i, x = 3 + 3 i

- 21 x^{2} + 31 x + 26 = 0

6 x^{2} + 240 = 0

2 0^{2} + 15 6^{2} = x^{2}

4 x^{2} - 6 = - 12 x

x^{2} - 2 x = - 3

What are the solutions to the equation (-1)/6 x^2+x-3=0 ?
The solutions to the equation (-1)/6 x^2+x-3=0 are x=3-3i,x=3+3i
Find the zeros of (-1)/6 x^2+x-3=0
The zeros of (-1)/6 x^2+x-3=0 are x=3-3i,x=3+3i