What are the solutions to the equation x(x-2)=120 ?

The solutions to the equation x(x-2)=120 are x=12,x=-10

Find the zeros of x(x-2)=120

The zeros of x(x-2)=120 are x=12,x=-10

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x (x - 2) = 120

x = 12, x = - 10

Solution steps

x (x - 2) = 120

Expand

x (x - 2) : x^{2} - 2 x

x^{2} - 2 x = 120

Move

120

to the left side

x^{2} - 2 x - 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 120 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 120) = 22

x_{1, 2} = \frac{- ( - 2 ) \pm 22}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 22}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 22}{2 \cdot 1}

x = \frac{- ( - 2 ) + 22}{2 \cdot 1} : 12

x = \frac{- ( - 2 ) - 22}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 12, x = - 10

- 4 x^{2} - 4 = 8 x

x^{2} - 8 x = 0

8 x^{2} - 10 x = - 9

2 x^{2} + x - 4 = 0, x^{2} + x = 0

3 x^{2} - 72 x + 324 = 0

What are the solutions to the equation x(x-2)=120 ?
The solutions to the equation x(x-2)=120 are x=12,x=-10
Find the zeros of x(x-2)=120
The zeros of x(x-2)=120 are x=12,x=-10