What are the solutions to the equation 2x^2=4x^2-72 ?

The solutions to the equation 2x^2=4x^2-72 are x=6,x=-6

Find the zeros of 2x^2=4x^2-72

The zeros of 2x^2=4x^2-72 are x=6,x=-6

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2 x^{2} = 4 x^{2} - 72

x = 6, x = - 6

Solution steps

2 x^{2} = 4 x^{2} - 72

Move

4 x^{2}

to the left side

- 2 x^{2} = - 72

Divide both sides by

- 2

x^{2} = 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 36, x = - 36

36 = 6

- 36 = - 6

x = 6, x = - 6

0 = x^{2} + 14 x + 49

(x + 20) \cdot (x - 20) = 3200

x, p = 3 x^{2} y^{3} z

2 x^{2} = 1 - 2 x

- 2 x^{2} + 120 x + 500 = 0

What are the solutions to the equation 2x^2=4x^2-72 ?
The solutions to the equation 2x^2=4x^2-72 are x=6,x=-6
Find the zeros of 2x^2=4x^2-72
The zeros of 2x^2=4x^2-72 are x=6,x=-6