What are the solutions to the equation x^2=-19x ?

The solutions to the equation x^2=-19x are x=0,x=-19

Find the zeros of x^2=-19x

The zeros of x^2=-19x are x=0,x=-19

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x^{2} = - 19 x

x = 0, x = - 19

Solution steps

x^{2} = - 19 x

Move

19 x

to the left side

x^{2} + 19 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1 9^{2} - 4 \cdot 1 \cdot 0 = 19

x_{1, 2} = \frac{- 19 \pm 19}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 19 + 19}{2 \cdot 1}, x_{2} = \frac{- 19 - 19}{2 \cdot 1}

x = \frac{- 19 + 19}{2 \cdot 1} : 0

x = \frac{- 19 - 19}{2 \cdot 1} : - 19

The solutions to the quadratic equation are:

x = 0, x = - 19

5 p^{2} - 5 = 2 p

x, F = x + (x^{2} + x y + 1) y

x^{2} = - 112

n^{2} = - 43

x^{2} - 8 x - 9 = 0

What are the solutions to the equation x^2=-19x ?
The solutions to the equation x^2=-19x are x=0,x=-19
Find the zeros of x^2=-19x
The zeros of x^2=-19x are x=0,x=-19