What are the solutions to the equation x(4x+7)=0 ?

The solutions to the equation x(4x+7)=0 are x=0,x=-7/4

Find the zeros of x(4x+7)=0

The zeros of x(4x+7)=0 are x=0,x=-7/4

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x (4 x + 7) = 0

x = 0, x = - \frac{7}{4}

Decimal Notation

x = 0, x = - 1.75

Solution steps

x (4 x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 4 x + 7 = 0

Solve

4 x + 7 = 0 : x = - \frac{7}{4}

The solutions to the quadratic equation are:

x = 0, x = - \frac{7}{4}

8 w^{2} + 6 w - 9 = 0

6 x^{2} - x + 5 = 0

(x^{2} - 3 x) = 0

2 x - 3 + x^{2} = 0

x, x^{2} + y^{2} + 7 x + 7 y + 48 = 0

What are the solutions to the equation x(4x+7)=0 ?
The solutions to the equation x(4x+7)=0 are x=0,x=-7/4
Find the zeros of x(4x+7)=0
The zeros of x(4x+7)=0 are x=0,x=-7/4