What are the solutions to the equation (x-2)^2+4=0 ?

The solutions to the equation (x-2)^2+4=0 are x=2i+2,x=-2i+2

Find the zeros of (x-2)^2+4=0

The zeros of (x-2)^2+4=0 are x=2i+2,x=-2i+2

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(x - 2)^{2} + 4 = 0

x = 2 i + 2, x = - 2 i + 2

Solution steps

(x - 2)^{2} + 4 = 0

Move

4

to the right side

(x - 2)^{2} = - 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = - 4 : x = 2 i + 2

Solve

x - 2 = - - 4 : x = - 2 i + 2

The solutions to the quadratic equation are:

x = 2 i + 2, x = - 2 i + 2

x, x^{2} - 9 y^{2} = 0

2 m^{2} - 33 = - 5 + m

m, m^{2} + 4 = 0

- (x + 9) (x - 9) = 0

28 X - 30 + 36 X - 126 + 48 - 5 X^{2} = 0

What are the solutions to the equation (x-2)^2+4=0 ?
The solutions to the equation (x-2)^2+4=0 are x=2i+2,x=-2i+2
Find the zeros of (x-2)^2+4=0
The zeros of (x-2)^2+4=0 are x=2i+2,x=-2i+2