What are the solutions to the equation 28X-30+36X-126+48-5X^2=0 ?

The solutions to the equation 28X-30+36X-126+48-5X^2=0 are X=2,X= 54/5

Find the zeros of 28X-30+36X-126+48-5X^2=0

The zeros of 28X-30+36X-126+48-5X^2=0 are X=2,X= 54/5

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28 X - 30 + 36 X - 126 + 48 - 5 X^{2} = 0

X = 2, X = \frac{54}{5}

Decimal Notation

X = 2, X = 10.8

Solution steps

28 X - 30 + 36 X - 126 + 48 - 5 X^{2} = 0

Refine

- 5 X^{2} + 64 X - 108 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 64 \pm 6 4 ^{2} - 4 ( - 5 ) ( - 108 )}{2 ( - 5 )}

6 4^{2} - 4 (- 5) (- 108) = 44

X_{1, 2} = \frac{- 64 \pm 44}{2 ( - 5 )}

Separate the solutions

X_{1} = \frac{- 64 + 44}{2 ( - 5 )}, X_{2} = \frac{- 64 - 44}{2 ( - 5 )}

X = \frac{- 64 + 44}{2 ( - 5 )} : 2

X = \frac{- 64 - 44}{2 ( - 5 )} : \frac{54}{5}

The solutions to the quadratic equation are:

X = 2, X = \frac{54}{5}

2 x^{2} - 13 x - 10 = 0

8 x^{2} + 26 x - 24 = 0

- 2 x^{2} - 196 = 0

2 x^{2} - 4 x + 2 = 2

(x + \frac{1}{2}) (\frac{3}{2} x - 1) = 0

What are the solutions to the equation 28X-30+36X-126+48-5X^2=0 ?
The solutions to the equation 28X-30+36X-126+48-5X^2=0 are X=2,X= 54/5
Find the zeros of 28X-30+36X-126+48-5X^2=0
The zeros of 28X-30+36X-126+48-5X^2=0 are X=2,X= 54/5