What are the solutions to the equation -4x^2=48 ?

The solutions to the equation -4x^2=48 are x=2sqrt(3)i,x=-2sqrt(3)i

Find the zeros of -4x^2=48

The zeros of -4x^2=48 are x=2sqrt(3)i,x=-2sqrt(3)i

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- 4 x^{2} = 48

x = 23 i, x = - 23 i

Solution steps

- 4 x^{2} = 48

Divide both sides by

- 4

x^{2} = - 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 12, x = - - 12

- 12 = 23 i

- - 12 = - 23 i

x = 23 i, x = - 23 i

5 x^{2} - 2 x - 3 = 0

c (x) = 2 x^{2} - 18 x + 680

9 x^{2} + 2 x - 2 = 0

9 x^{2} = 5

x, 4 x^{2} - 8 x + 1 = 0

What are the solutions to the equation -4x^2=48 ?
The solutions to the equation -4x^2=48 are x=2sqrt(3)i,x=-2sqrt(3)i
Find the zeros of -4x^2=48
The zeros of -4x^2=48 are x=2sqrt(3)i,x=-2sqrt(3)i