What are the solutions to the equation quadraticformula 5x^2-2x-3=0 ?

The solutions to the equation quadraticformula 5x^2-2x-3=0 are x=1,x=-3/5

Find the zeros of quadraticformula 5x^2-2x-3=0

The zeros of quadraticformula 5x^2-2x-3=0 are x=1,x=-3/5

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5 x^{2} - 2 x - 3 = 0

x = 1, x = - \frac{3}{5}

Decimal Notation

x = 1, x = - 0.6

Solution steps

5 x^{2} - 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 5 ( - 3 )}{2 \cdot 5}

(- 2)^{2} - 4 \cdot 5 (- 3) = 8

x_{1, 2} = \frac{- ( - 2 ) \pm 8}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 8}{2 \cdot 5}, x_{2} = \frac{- ( - 2 ) - 8}{2 \cdot 5}

x = \frac{- ( - 2 ) + 8}{2 \cdot 5} : 1

x = \frac{- ( - 2 ) - 8}{2 \cdot 5} : - \frac{3}{5}

The solutions to the quadratic equation are:

x = 1, x = - \frac{3}{5}

c (x) = 2 x^{2} - 18 x + 680

9 x^{2} + 2 x - 2 = 0

9 x^{2} = 5

x, 4 x^{2} - 8 x + 1 = 0

4 x^{2} + 8 x - 1 = 0

What are the solutions to the equation quadraticformula 5x^2-2x-3=0 ?
The solutions to the equation quadraticformula 5x^2-2x-3=0 are x=1,x=-3/5
Find the zeros of quadraticformula 5x^2-2x-3=0
The zeros of quadraticformula 5x^2-2x-3=0 are x=1,x=-3/5