What are the solutions to the equation completesquare 4x^2+8x-1=0 ?

The solutions to the equation completesquare 4x^2+8x-1=0 are x=(sqrt(5))/2-1,x=-(sqrt(5))/2-1

Find the zeros of completesquare 4x^2+8x-1=0

The zeros of completesquare 4x^2+8x-1=0 are x=(sqrt(5))/2-1,x=-(sqrt(5))/2-1

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4 x^{2} + 8 x - 1 = 0

x = \frac{5}{2} - 1, x = - \frac{5}{2} - 1

Decimal Notation

x = 0.11803 \dots, x = - 2.11803 \dots

Solution steps

4 x^{2} + 8 x - 1 = 0

Move

1

to the right side

4 x^{2} + 8 x = 1

Divide both sides by

4

\frac{4 x ^{2} + 8 x}{4} = \frac{1}{4}

x^{2} + 2 x = \frac{1}{4}

Rewrite in the form

(x + a)^{2} = b

(x + 1)^{2} = \frac{5}{4}

For

the solutions are

f (x) = a, - a

Solve

x + 1 = \frac{5}{4} : x = \frac{5}{2} - 1

Solve

x + 1 = - \frac{5}{4} : x = - \frac{5}{2} - 1

The solutions to the quadratic equation are:

x = \frac{5}{2} - 1, x = - \frac{5}{2} - 1

5 x^{2} - 15 x - 30 = 0

a^{2} + 7 a - 18 = 0

\frac{x ^{2}}{2} - 23 = - x + 1

x, (x^{2} + 4) y + x y = 4 x

x, 3 x^{2} - 4 x y + 4 y^{2} + 8 x - 1 = 0

What are the solutions to the equation completesquare 4x^2+8x-1=0 ?
The solutions to the equation completesquare 4x^2+8x-1=0 are x=(sqrt(5))/2-1,x=-(sqrt(5))/2-1
Find the zeros of completesquare 4x^2+8x-1=0
The zeros of completesquare 4x^2+8x-1=0 are x=(sqrt(5))/2-1,x=-(sqrt(5))/2-1