What are the solutions to the equation a^2+7a-18=0 ?

The solutions to the equation a^2+7a-18=0 are a=2,a=-9

Find the zeros of a^2+7a-18=0

The zeros of a^2+7a-18=0 are a=2,a=-9

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a^{2} + 7 a - 18 = 0

a = 2, a = - 9

Solution steps

a^{2} + 7 a - 18 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 18) = 11

a_{1, 2} = \frac{- 7 \pm 11}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 7 + 11}{2 \cdot 1}, a_{2} = \frac{- 7 - 11}{2 \cdot 1}

a = \frac{- 7 + 11}{2 \cdot 1} : 2

a = \frac{- 7 - 11}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

a = 2, a = - 9

\frac{x ^{2}}{2} - 23 = - x + 1

x, (x^{2} + 4) y + x y = 4 x

x, 3 x^{2} - 4 x y + 4 y^{2} + 8 x - 1 = 0

4 x^{2} - 21 x + 20 = 0

x, 0 = \frac{1}{2} (x^{2} + y^{2})

What are the solutions to the equation a^2+7a-18=0 ?
The solutions to the equation a^2+7a-18=0 are a=2,a=-9
Find the zeros of a^2+7a-18=0
The zeros of a^2+7a-18=0 are a=2,a=-9