What are the solutions to the equation a^2+x^2=1^2 ?

The solutions to the equation a^2+x^2=1^2 are x=sqrt(1-a^2),x=-sqrt(1-a^2)

Find the zeros of a^2+x^2=1^2

The zeros of a^2+x^2=1^2 are x=sqrt(1-a^2),x=-sqrt(1-a^2)

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a^{2} + x^{2} = 1^{2}

x = 1 - a^{2}, x = - 1 - a^{2}

Solution steps

a^{2} + x^{2} = 1^{2}

Move

a^{2}

to the right side

x^{2} = 1 - a^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1 - a^{2}, x = - 1 - a^{2}

2 x^{2} - 4 x + 4 = 4

x^{2} + 4 - 3 x = 0

2 x^{2} + (k + 2) x + \frac{1}{8} = 0

5 x^{2} + 28 x - 12 = 0

(x - 2)^{2} + 1 = 0

What are the solutions to the equation a^2+x^2=1^2 ?
The solutions to the equation a^2+x^2=1^2 are x=sqrt(1-a^2),x=-sqrt(1-a^2)
Find the zeros of a^2+x^2=1^2
The zeros of a^2+x^2=1^2 are x=sqrt(1-a^2),x=-sqrt(1-a^2)