What are the solutions to the equation solvefor x,x^2+6mx+m=0 ?

The solutions to the equation solvefor x,x^2+6mx+m=0 are x=-3m+sqrt(m(9m-1)),x=-3m-sqrt(m(9m-1))

Find the zeros of solvefor x,x^2+6mx+m=0

The zeros of solvefor x,x^2+6mx+m=0 are x=-3m+sqrt(m(9m-1)),x=-3m-sqrt(m(9m-1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x, x^{2} + 6 m x + m = 0

x = - 3 m + m (9 m - 1), x = - 3 m - m (9 m - 1)

Solution steps

x^{2} + 6 m x + m = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 m \pm ( 6 m ) ^{2} - 4 \cdot 1 \cdot m}{2 \cdot 1}

Simplify

(6 m)^{2} - 4 \cdot 1 \cdot m : 2 m (9 m - 1)

x_{1, 2} = \frac{- 6 m \pm 2 m ( 9 m - 1 )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 m + 2 m ( 9 m - 1 )}{2 \cdot 1}, x_{2} = \frac{- 6 m - 2 m ( 9 m - 1 )}{2 \cdot 1}

x = \frac{- 6 m + 2 m ( 9 m - 1 )}{2 \cdot 1} : - 3 m + m (9 m - 1)

x = \frac{- 6 m - 2 m ( 9 m - 1 )}{2 \cdot 1} : - 3 m - m (9 m - 1)

The solutions to the quadratic equation are:

x = - 3 m + m (9 m - 1), x = - 3 m - m (9 m - 1)

x^{2} = 1 2^{2} + 1 3^{2}

x = x^{2} - 24 x + 144

4 x + \frac{2}{3} x^{2} - 1 = 0

(1 - x^{2}) \cdot (- 3 - x^{3} - 2) = 0

a^{2} + 1 0^{2} = 1 6^{2}

What are the solutions to the equation solvefor x,x^2+6mx+m=0 ?
The solutions to the equation solvefor x,x^2+6mx+m=0 are x=-3m+sqrt(m(9m-1)),x=-3m-sqrt(m(9m-1))
Find the zeros of solvefor x,x^2+6mx+m=0
The zeros of solvefor x,x^2+6mx+m=0 are x=-3m+sqrt(m(9m-1)),x=-3m-sqrt(m(9m-1))