What are the solutions to the equation x(x+36)=5152 ?

The solutions to the equation x(x+36)=5152 are x=56,x=-92

Find the zeros of x(x+36)=5152

The zeros of x(x+36)=5152 are x=56,x=-92

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x (x + 36) = 5152

x = 56, x = - 92

Solution steps

x (x + 36) = 5152

Expand

x (x + 36) : x^{2} + 36 x

x^{2} + 36 x = 5152

Move

5152

to the left side

x^{2} + 36 x - 5152 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 1 \cdot ( - 5152 )}{2 \cdot 1}

3 6^{2} - 4 \cdot 1 \cdot (- 5152) = 148

x_{1, 2} = \frac{- 36 \pm 148}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 36 + 148}{2 \cdot 1}, x_{2} = \frac{- 36 - 148}{2 \cdot 1}

x = \frac{- 36 + 148}{2 \cdot 1} : 56

x = \frac{- 36 - 148}{2 \cdot 1} : - 92

The solutions to the quadratic equation are:

x = 56, x = - 92

x^{2} = 7^{2} + 5^{2}

2 X^{2} - X + 3 = 0

x, x^{2} + y^{2} - 2 h x = 0

n^{2} - 3 n - 18 = 0

15 x^{2} - 9 = 0

What are the solutions to the equation x(x+36)=5152 ?
The solutions to the equation x(x+36)=5152 are x=56,x=-92
Find the zeros of x(x+36)=5152
The zeros of x(x+36)=5152 are x=56,x=-92