What are the solutions to the equation solvefor x,x^2+y^2-2hx=0 ?

The solutions to the equation solvefor x,x^2+y^2-2hx=0 are x=h+sqrt(-y^2+h^2),x=h-sqrt(-y^2+h^2)

Find the zeros of solvefor x,x^2+y^2-2hx=0

The zeros of solvefor x,x^2+y^2-2hx=0 are x=h+sqrt(-y^2+h^2),x=h-sqrt(-y^2+h^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

x, x^{2} + y^{2} - 2 h x = 0

x = h + - y^{2} + h^{2}, x = h - - y^{2} + h^{2}

Solution steps

x^{2} + y^{2} - 2 h x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 h x + y^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 h ) \pm ( - 2 h ) ^{2} - 4 \cdot 1 \cdot y ^{2}}{2 \cdot 1}

Simplify

(- 2 h)^{2} - 4 \cdot 1 \cdot y^{2} : 2 h^{2} - y^{2}

x_{1, 2} = \frac{- ( - 2 h ) \pm 2 h ^{2} - y ^{2}}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 h ) + 2 h ^{2} - y ^{2}}{2 \cdot 1}, x_{2} = \frac{- ( - 2 h ) - 2 h ^{2} - y ^{2}}{2 \cdot 1}

x = \frac{- ( - 2 h ) + 2 h ^{2} - y ^{2}}{2 \cdot 1} : h + - y^{2} + h^{2}

x = \frac{- ( - 2 h ) - 2 h ^{2} - y ^{2}}{2 \cdot 1} : h - - y^{2} + h^{2}

The solutions to the quadratic equation are:

x = h + - y^{2} + h^{2}, x = h - - y^{2} + h^{2}

n^{2} - 3 n - 18 = 0

15 x^{2} - 9 = 0

b^{2} - 5 b - 50 = 0

3 s^{2} + 9 s + 2 = 0

a, (128 (a + b) + 3)^{2} + 3 = 64

What are the solutions to the equation solvefor x,x^2+y^2-2hx=0 ?
The solutions to the equation solvefor x,x^2+y^2-2hx=0 are x=h+sqrt(-y^2+h^2),x=h-sqrt(-y^2+h^2)
Find the zeros of solvefor x,x^2+y^2-2hx=0
The zeros of solvefor x,x^2+y^2-2hx=0 are x=h+sqrt(-y^2+h^2),x=h-sqrt(-y^2+h^2)