What are the solutions to the equation 3s^2+9s+2=0 ?

The solutions to the equation 3s^2+9s+2=0 are s=(-9+sqrt(57))/6 ,s=(-9-sqrt(57))/6

Find the zeros of 3s^2+9s+2=0

The zeros of 3s^2+9s+2=0 are s=(-9+sqrt(57))/6 ,s=(-9-sqrt(57))/6

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3 s^{2} + 9 s + 2 = 0

s = \frac{- 9 + 57}{6}, s = \frac{- 9 - 57}{6}

Decimal Notation

s = - 0.24169 \dots, s = - 2.75830 \dots

Solution steps

3 s^{2} + 9 s + 2 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

9^{2} - 4 \cdot 3 \cdot 2 = 57

s_{1, 2} = \frac{- 9 \pm 57}{2 \cdot 3}

Separate the solutions

s_{1} = \frac{- 9 + 57}{2 \cdot 3}, s_{2} = \frac{- 9 - 57}{2 \cdot 3}

s = \frac{- 9 + 57}{2 \cdot 3} : \frac{- 9 + 57}{6}

s = \frac{- 9 - 57}{2 \cdot 3} : \frac{- 9 - 57}{6}

The solutions to the quadratic equation are:

s = \frac{- 9 + 57}{6}, s = \frac{- 9 - 57}{6}

a, (128 (a + b) + 3)^{2} + 3 = 64

t^{2} - 4 t

x^{2} - 100 x + 4700 = 0

(2 x + 1) (x - 7) = - 8 x

x^{2} + 6 x = 16

What are the solutions to the equation 3s^2+9s+2=0 ?
The solutions to the equation 3s^2+9s+2=0 are s=(-9+sqrt(57))/6 ,s=(-9-sqrt(57))/6
Find the zeros of 3s^2+9s+2=0
The zeros of 3s^2+9s+2=0 are s=(-9+sqrt(57))/6 ,s=(-9-sqrt(57))/6