What are the solutions to the equation (2x+1)(x-7)=-8x ?

The solutions to the equation (2x+1)(x-7)=-8x are x= 7/2 ,x=-1

Find the zeros of (2x+1)(x-7)=-8x

The zeros of (2x+1)(x-7)=-8x are x= 7/2 ,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2 x + 1) (x - 7) = - 8 x

x = \frac{7}{2}, x = - 1

Decimal Notation

x = 3.5, x = - 1

Solution steps

(2 x + 1) (x - 7) = - 8 x

Expand

(2 x + 1) (x - 7) : 2 x^{2} - 13 x - 7

2 x^{2} - 13 x - 7 = - 8 x

Move

8 x

to the left side

2 x^{2} - 5 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 7 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 7) = 9

x_{1, 2} = \frac{- ( - 5 ) \pm 9}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 9}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 9}{2 \cdot 2}

x = \frac{- ( - 5 ) + 9}{2 \cdot 2} : \frac{7}{2}

x = \frac{- ( - 5 ) - 9}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = - 1

x^{2} + 6 x = 16

g^{2} + 4 g + 4 = 0

(y - 3)^{2} = 4 y - 12

x, x^{2} - 5 x - 6 = 0

7 x^{2} - 29 x = - 4

What are the solutions to the equation (2x+1)(x-7)=-8x ?
The solutions to the equation (2x+1)(x-7)=-8x are x= 7/2 ,x=-1
Find the zeros of (2x+1)(x-7)=-8x
The zeros of (2x+1)(x-7)=-8x are x= 7/2 ,x=-1