What are the solutions to the equation g^2+4g+4=0 ?

The solutions to the equation g^2+4g+4=0 are g=-2

Find the zeros of g^2+4g+4=0

The zeros of g^2+4g+4=0 are g=-2

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g^{2} + 4 g + 4 = 0

g = - 2

Solution steps

g^{2} + 4 g + 4 = 0

Solve with the quadratic formula

g_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

g_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

g = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

g = - 2

The solution to the quadratic equation is:

g = - 2

(y - 3)^{2} = 4 y - 12

x, x^{2} - 5 x - 6 = 0

7 x^{2} - 29 x = - 4

2 X^{2} - 8 = 0

v^{2} + 8 v + 7 = 0

What are the solutions to the equation g^2+4g+4=0 ?
The solutions to the equation g^2+4g+4=0 are g=-2
Find the zeros of g^2+4g+4=0
The zeros of g^2+4g+4=0 are g=-2