What are the solutions to the equation 7x^2-29x=-4 ?

The solutions to the equation 7x^2-29x=-4 are x=4,x= 1/7

Find the zeros of 7x^2-29x=-4

The zeros of 7x^2-29x=-4 are x=4,x= 1/7

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7 x^{2} - 29 x = - 4

x = 4, x = \frac{1}{7}

Decimal Notation

x = 4, x = 0.14285 \dots

Solution steps

7 x^{2} - 29 x = - 4

Move

4

to the left side

7 x^{2} - 29 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 7 \cdot 4}{2 \cdot 7}

(- 29)^{2} - 4 \cdot 7 \cdot 4 = 27

x_{1, 2} = \frac{- ( - 29 ) \pm 27}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 29 ) + 27}{2 \cdot 7}, x_{2} = \frac{- ( - 29 ) - 27}{2 \cdot 7}

x = \frac{- ( - 29 ) + 27}{2 \cdot 7} : 4

x = \frac{- ( - 29 ) - 27}{2 \cdot 7} : \frac{1}{7}

The solutions to the quadratic equation are:

x = 4, x = \frac{1}{7}

2 X^{2} - 8 = 0

v^{2} + 8 v + 7 = 0

2 + 24.5 x - 4.9 x^{2} = 0

x, x^{2} - x y + y^{2} = 19

x^{2} - 35 x = 0

What are the solutions to the equation 7x^2-29x=-4 ?
The solutions to the equation 7x^2-29x=-4 are x=4,x= 1/7
Find the zeros of 7x^2-29x=-4
The zeros of 7x^2-29x=-4 are x=4,x= 1/7