What are the solutions to the equation 3v^2+6v+3=0 ?

The solutions to the equation 3v^2+6v+3=0 are v=-1

Find the zeros of 3v^2+6v+3=0

The zeros of 3v^2+6v+3=0 are v=-1

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3 v^{2} + 6 v + 3 = 0

v = - 1

Solution steps

3 v^{2} + 6 v + 3 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

6^{2} - 4 \cdot 3 \cdot 3 = 0

v_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 3}

v = \frac{- 6}{2 \cdot 3}

\frac{- 6}{2 \cdot 3} = - 1

v = - 1

The solution to the quadratic equation is:

v = - 1

r^{2} + 10 r + 50 = 0

49 + 16 m^{2} - 256 m = 0

- 4 + z^{2} = 16

2 x^{2} - 9 x = - 12

- 2 x^{2} - 2 x + 24 = 0

What are the solutions to the equation 3v^2+6v+3=0 ?
The solutions to the equation 3v^2+6v+3=0 are v=-1
Find the zeros of 3v^2+6v+3=0
The zeros of 3v^2+6v+3=0 are v=-1