What are the solutions to the equation -4+z^2=16 ?

The solutions to the equation -4+z^2=16 are z=2sqrt(5),z=-2sqrt(5)

Find the zeros of -4+z^2=16

The zeros of -4+z^2=16 are z=2sqrt(5),z=-2sqrt(5)

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- 4 + z^{2} = 16

z = 25, z = - 25

Decimal Notation

z = 4.47213 \dots, z = - 4.47213 \dots

Solution steps

- 4 + z^{2} = 16

Move

4

to the right side

z^{2} = 20

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = 20, z = - 20

20 = 25

- 20 = - 25

z = 25, z = - 25

2 x^{2} - 9 x = - 12

- 2 x^{2} - 2 x + 24 = 0

6 x^{2} + 7 x - j = 0

0 = 32 x - 16 x^{2}

(3 - x) (3 - x) - 1 = 0

What are the solutions to the equation -4+z^2=16 ?
The solutions to the equation -4+z^2=16 are z=2sqrt(5),z=-2sqrt(5)
Find the zeros of -4+z^2=16
The zeros of -4+z^2=16 are z=2sqrt(5),z=-2sqrt(5)