What are the solutions to the equation 6x^2+7x-j=0 ?

The solutions to the equation 6x^2+7x-j=0 are x=(-7+sqrt(49+24j))/(12),x=(-7-sqrt(49+24j))/(12)

Find the zeros of 6x^2+7x-j=0

The zeros of 6x^2+7x-j=0 are x=(-7+sqrt(49+24j))/(12),x=(-7-sqrt(49+24j))/(12)

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6 x^{2} + 7 x - j = 0

x = \frac{- 7 + 49 + 24 j}{12}, x = \frac{- 7 - 49 + 24 j}{12}

Solution steps

6 x^{2} + 7 x - j = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 6 ( - j )}{2 \cdot 6}

Simplify

7^{2} - 4 \cdot 6 (- j) : 49 + 24 j

x_{1, 2} = \frac{- 7 \pm 49 + 24 j}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 7 + 49 + 24 j}{2 \cdot 6}, x_{2} = \frac{- 7 - 49 + 24 j}{2 \cdot 6}

x = \frac{- 7 + 49 + 24 j}{2 \cdot 6} : \frac{- 7 + 49 + 24 j}{12}

x = \frac{- 7 - 49 + 24 j}{2 \cdot 6} : \frac{- 7 - 49 + 24 j}{12}

The solutions to the quadratic equation are:

x = \frac{- 7 + 49 + 24 j}{12}, x = \frac{- 7 - 49 + 24 j}{12}

0 = 32 x - 16 x^{2}

(3 - x) (3 - x) - 1 = 0

- x^{2} + 4 x - 9

- x^{2} + 4 x - 5

- x^{2} + 4 x + 1

What are the solutions to the equation 6x^2+7x-j=0 ?
The solutions to the equation 6x^2+7x-j=0 are x=(-7+sqrt(49+24j))/(12),x=(-7-sqrt(49+24j))/(12)
Find the zeros of 6x^2+7x-j=0
The zeros of 6x^2+7x-j=0 are x=(-7+sqrt(49+24j))/(12),x=(-7-sqrt(49+24j))/(12)