What are the solutions to the equation completesquare 3x^2-12x+8=0 ?

The solutions to the equation completesquare 3x^2-12x+8=0 are x= 2/(sqrt(3))+2,x=-2/(sqrt(3))+2

Find the zeros of completesquare 3x^2-12x+8=0

The zeros of completesquare 3x^2-12x+8=0 are x= 2/(sqrt(3))+2,x=-2/(sqrt(3))+2

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3 x^{2} - 12 x + 8 = 0

x = \frac{2}{3} + 2, x = - \frac{2}{3} + 2

Decimal Notation

x = 3.15470 \dots, x = 0.84529 \dots

Solution steps

3 x^{2} - 12 x + 8 = 0

Move

8

to the right side

3 x^{2} - 12 x = - 8

Divide both sides by

3

\frac{3 x ^{2} - 12 x}{3} = \frac{- 8}{3}

x^{2} - 4 x = - \frac{8}{3}

Rewrite in the form

(x + a)^{2} = b

(x - 2)^{2} = \frac{4}{3}

For

the solutions are

f (x) = a, - a

Solve

x - 2 = \frac{4}{3} : x = \frac{2}{3} + 2

Solve

x - 2 = - \frac{4}{3} : x = - \frac{2}{3} + 2

The solutions to the quadratic equation are:

x = \frac{2}{3} + 2, x = - \frac{2}{3} + 2

- x^{2} + 21 x = 0

n^{2} + 3 n = 40

6 x^{2} - 150 x + 396 = 0

35 b^{2} - 8 = 6 b

(x - 3)^{2} = 2 (17 - 3 x)

What are the solutions to the equation completesquare 3x^2-12x+8=0 ?
The solutions to the equation completesquare 3x^2-12x+8=0 are x= 2/(sqrt(3))+2,x=-2/(sqrt(3))+2
Find the zeros of completesquare 3x^2-12x+8=0
The zeros of completesquare 3x^2-12x+8=0 are x= 2/(sqrt(3))+2,x=-2/(sqrt(3))+2