What are the solutions to the equation r^2+8r+5=0 ?

The solutions to the equation r^2+8r+5=0 are r=-4+sqrt(11),r=-4-sqrt(11)

Find the zeros of r^2+8r+5=0

The zeros of r^2+8r+5=0 are r=-4+sqrt(11),r=-4-sqrt(11)

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r^{2} + 8 r + 5 = 0

r = - 4 + 11, r = - 4 - 11

Decimal Notation

r = - 0.68337 \dots, r = - 7.31662 \dots

Solution steps

r^{2} + 8 r + 5 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 5 = 211

r_{1, 2} = \frac{- 8 \pm 2 11}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 8 + 2 11}{2 \cdot 1}, r_{2} = \frac{- 8 - 2 11}{2 \cdot 1}

r = \frac{- 8 + 2 11}{2 \cdot 1} : - 4 + 11

r = \frac{- 8 - 2 11}{2 \cdot 1} : - 4 - 11

The solutions to the quadratic equation are:

r = - 4 + 11, r = - 4 - 11

6 x^{2} - 7 x - 24 = 0

(3 - x) (2 - x) - 12 = 0

1400 - 3 x^{2} = 0

t^{2} - 3 t - 40 = 0

4 x^{2} - 3 x + 8 = 0

What are the solutions to the equation r^2+8r+5=0 ?
The solutions to the equation r^2+8r+5=0 are r=-4+sqrt(11),r=-4-sqrt(11)
Find the zeros of r^2+8r+5=0
The zeros of r^2+8r+5=0 are r=-4+sqrt(11),r=-4-sqrt(11)