What are the solutions to the equation (z^2)/6-z/2-45=0 ?

The solutions to the equation (z^2)/6-z/2-45=0 are z=18,z=-15

Find the zeros of (z^2)/6-z/2-45=0

The zeros of (z^2)/6-z/2-45=0 are z=18,z=-15

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{z ^{2}}{6} - \frac{z}{2} - 45 = 0

z = 18, z = - 15

Solution steps

\frac{z ^{2}}{6} - \frac{z}{2} - 45 = 0

Find Least Common Multiplier of

6, 2 : 6

Multiply by LCM=

6

\frac{z ^{2}}{6} \cdot 6 - \frac{z}{2} \cdot 6 - 45 \cdot 6 = 0 \cdot 6

Simplify

z^{2} - 3 z - 270 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 270 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 270) = 33

z_{1, 2} = \frac{- ( - 3 ) \pm 33}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 3 ) + 33}{2 \cdot 1}, z_{2} = \frac{- ( - 3 ) - 33}{2 \cdot 1}

z = \frac{- ( - 3 ) + 33}{2 \cdot 1} : 18

z = \frac{- ( - 3 ) - 33}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

z = 18, z = - 15

m^{2} + 1.25 m = 0

3 t^{2} + 6 t = 0

s^{2} - 12 s + 61

8 x^{2} - 18 x = - 8

20 = - 1.9 t^{2} + 18 t + 1

What are the solutions to the equation (z^2)/6-z/2-45=0 ?
The solutions to the equation (z^2)/6-z/2-45=0 are z=18,z=-15
Find the zeros of (z^2)/6-z/2-45=0
The zeros of (z^2)/6-z/2-45=0 are z=18,z=-15