What are the solutions to the equation (3x-1)(2x)+(2x)=0 ?

The solutions to the equation (3x-1)(2x)+(2x)=0 are x=0

Find the zeros of (3x-1)(2x)+(2x)=0

The zeros of (3x-1)(2x)+(2x)=0 are x=0

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(3 x - 1) (2 x) + (2 x) = 0

x = 0

Solution steps

(3 x - 1) (2 x) + (2 x) = 0

Expand

(3 x - 1) (2 x) + (2 x) : 6 x^{2}

6 x^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 6 \cdot 0}{2 \cdot 6}

0^{2} - 4 \cdot 6 \cdot 0 = 0

x_{1, 2} = \frac{- 0 \pm 0}{2 \cdot 6}

x = \frac{- 0}{2 \cdot 6}

\frac{- 0}{2 \cdot 6} = 0

x = 0

The solution to the quadratic equation is:

x = 0

2 a^{2} + 15 a + 7 = 0

x^{2} - 0.4 x - 1.2 = 0

2 x (x + 5) = 45

D, (x^{2} D^{2} - 4 x D - 6 I) y = 0

(x - 2)^{2} = 8 (x - 2)

What are the solutions to the equation (3x-1)(2x)+(2x)=0 ?
The solutions to the equation (3x-1)(2x)+(2x)=0 are x=0
Find the zeros of (3x-1)(2x)+(2x)=0
The zeros of (3x-1)(2x)+(2x)=0 are x=0