What are the solutions to the equation factor 3x(2x+5)=4+5x ?

The solutions to the equation factor 3x(2x+5)=4+5x are x= 1/3 ,x=-2

Find the zeros of factor 3x(2x+5)=4+5x

The zeros of factor 3x(2x+5)=4+5x are x= 1/3 ,x=-2

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3 x (2 x + 5) = 4 + 5 x

x = \frac{1}{3}, x = - 2

Decimal Notation

x = 0.33333 \dots, x = - 2

Solution steps

3 x (2 x + 5) = 4 + 5 x

Expand

3 x (2 x + 5) : 6 x^{2} + 15 x

6 x^{2} + 15 x = 4 + 5 x

Move

5 x

to the left side

6 x^{2} + 10 x = 4

Move

4

to the left side

6 x^{2} + 10 x - 4 = 0

Factor

6 x^{2} + 10 x - 4 : 2 (3 x - 1) (x + 2)

2 (3 x - 1) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 1 = 0 or x + 2 = 0

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

x + 2 = 0 : x = - 2

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = - 2

x^{2} - 12 x + 35 = 0

- x^{2} + 6 x + 11

8 x^{2} + 3 x - 9 = 0

x^{2} + 4 x + 4 = 128

0 = x^{2} - 12 x + 24

What are the solutions to the equation factor 3x(2x+5)=4+5x ?
The solutions to the equation factor 3x(2x+5)=4+5x are x= 1/3 ,x=-2
Find the zeros of factor 3x(2x+5)=4+5x
The zeros of factor 3x(2x+5)=4+5x are x= 1/3 ,x=-2