What are the solutions to the equation z^2-14z=-17 ?

The solutions to the equation z^2-14z=-17 are z=7+4sqrt(2),z=7-4sqrt(2)

Find the zeros of z^2-14z=-17

The zeros of z^2-14z=-17 are z=7+4sqrt(2),z=7-4sqrt(2)

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z^{2} - 14 z = - 17

z = 7 + 42, z = 7 - 42

Decimal Notation

z = 12.65685 \dots, z = 1.34314 \dots

Solution steps

z^{2} - 14 z = - 17

Move

17

to the left side

z^{2} - 14 z + 17 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 17}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 17 = 82

z_{1, 2} = \frac{- ( - 14 ) \pm 8 2}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 14 ) + 8 2}{2 \cdot 1}, z_{2} = \frac{- ( - 14 ) - 8 2}{2 \cdot 1}

z = \frac{- ( - 14 ) + 8 2}{2 \cdot 1} : 7 + 42

z = \frac{- ( - 14 ) - 8 2}{2 \cdot 1} : 7 - 42

The solutions to the quadratic equation are:

z = 7 + 42, z = 7 - 42

3 x^{2} - 6 x - 15 = 0

x^{2} - \frac{2 x}{5} - 4 = 0

(4 x - 40)^{2} = 48

3 π x - 1.1 x^{2} - λ x = 0

7 x - 3 x^{2} = 85 + 2 x^{2} + 2 x

What are the solutions to the equation z^2-14z=-17 ?
The solutions to the equation z^2-14z=-17 are z=7+4sqrt(2),z=7-4sqrt(2)
Find the zeros of z^2-14z=-17
The zeros of z^2-14z=-17 are z=7+4sqrt(2),z=7-4sqrt(2)