What are the solutions to the equation 3x(x-2)+9(x-2)=0 ?

The solutions to the equation 3x(x-2)+9(x-2)=0 are x=2,x=-3

Find the zeros of 3x(x-2)+9(x-2)=0

The zeros of 3x(x-2)+9(x-2)=0 are x=2,x=-3

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3 x (x - 2) + 9 (x - 2) = 0

x = 2, x = - 3

Solution steps

3 x (x - 2) + 9 (x - 2) = 0

Expand

3 x (x - 2) + 9 (x - 2) : 3 x^{2} + 3 x - 18

3 x^{2} + 3 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 3 ( - 18 )}{2 \cdot 3}

3^{2} - 4 \cdot 3 (- 18) = 15

x_{1, 2} = \frac{- 3 \pm 15}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 3 + 15}{2 \cdot 3}, x_{2} = \frac{- 3 - 15}{2 \cdot 3}

x = \frac{- 3 + 15}{2 \cdot 3} : 2

x = \frac{- 3 - 15}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

x = 2, x = - 3

x^{2} + a x + b

k^{2} - k - 56 = 0

r^{2} = 3^{2} + (- 4)^{2}

x, (f \circ g) = (π - x)^{2} - π

3 x^{2} + 2 x^{2} = 6

What are the solutions to the equation 3x(x-2)+9(x-2)=0 ?
The solutions to the equation 3x(x-2)+9(x-2)=0 are x=2,x=-3
Find the zeros of 3x(x-2)+9(x-2)=0
The zeros of 3x(x-2)+9(x-2)=0 are x=2,x=-3