What are the solutions to the equation k^2-k-56=0 ?

The solutions to the equation k^2-k-56=0 are k=8,k=-7

Find the zeros of k^2-k-56=0

The zeros of k^2-k-56=0 are k=8,k=-7

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k^{2} - k - 56 = 0

k = 8, k = - 7

Solution steps

k^{2} - k - 56 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 56 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 56) = 15

k_{1, 2} = \frac{- ( - 1 ) \pm 15}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 1 ) + 15}{2 \cdot 1}, k_{2} = \frac{- ( - 1 ) - 15}{2 \cdot 1}

k = \frac{- ( - 1 ) + 15}{2 \cdot 1} : 8

k = \frac{- ( - 1 ) - 15}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

k = 8, k = - 7

r^{2} = 3^{2} + (- 4)^{2}

x, (f \circ g) = (π - x)^{2} - π

3 x^{2} + 2 x^{2} = 6

- x^{2} - 4 x - 2 = 0

x, - 4 x^{2} - 4 x - 1 = 0

What are the solutions to the equation k^2-k-56=0 ?
The solutions to the equation k^2-k-56=0 are k=8,k=-7
Find the zeros of k^2-k-56=0
The zeros of k^2-k-56=0 are k=8,k=-7