What are the solutions to the equation 8(x-9)^2+11=-10 ?

The solutions to the equation 8(x-9)^2+11=-10 are x=9+i(sqrt(42))/4 ,x=9-i(sqrt(42))/4

Find the zeros of 8(x-9)^2+11=-10

The zeros of 8(x-9)^2+11=-10 are x=9+i(sqrt(42))/4 ,x=9-i(sqrt(42))/4

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8 (x - 9)^{2} + 11 = - 10

x = 9 + i \frac{42}{4}, x = 9 - i \frac{42}{4}

Solution steps

8 (x - 9)^{2} + 11 = - 10

Move

11

to the right side

8 (x - 9)^{2} = - 21

Divide both sides by

8

(x - 9)^{2} = - \frac{21}{8}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 9 = - \frac{21}{8} : x = 9 + i \frac{42}{4}

Solve

x - 9 = - - \frac{21}{8} : x = 9 - i \frac{42}{4}

The solutions to the quadratic equation are:

x = 9 + i \frac{42}{4}, x = 9 - i \frac{42}{4}

6 x^{2} - x - 6 = 0

5 x^{2} = 320

- x^{2} - 2 x - 2 = 2 x

6 x^{2} - 4 x + 11 = 0

x^{2} = 5^{2} + 8^{2}

What are the solutions to the equation 8(x-9)^2+11=-10 ?
The solutions to the equation 8(x-9)^2+11=-10 are x=9+i(sqrt(42))/4 ,x=9-i(sqrt(42))/4
Find the zeros of 8(x-9)^2+11=-10
The zeros of 8(x-9)^2+11=-10 are x=9+i(sqrt(42))/4 ,x=9-i(sqrt(42))/4