What are the solutions to the equation -x^2-sqrt(2)x-2=sqrt(2)x ?

The solutions to the equation -x^2-sqrt(2)x-2=sqrt(2)x are x=-sqrt(2)

Find the zeros of -x^2-sqrt(2)x-2=sqrt(2)x

The zeros of -x^2-sqrt(2)x-2=sqrt(2)x are x=-sqrt(2)

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- x^{2} - 2 x - 2 = 2 x

x = - 2

Decimal Notation

x = - 1.41421 \dots

Solution steps

- x^{2} - 2 x - 2 = 2 x

Move

2 x

to the left side

- x^{2} - 22 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 2 ) \pm ( - 2 2 ) ^{2} - 4 ( - 1 ) ( - 2 )}{2 ( - 1 )}

(- 22)^{2} - 4 (- 1) (- 2) = 0

x_{1, 2} = \frac{- ( - 2 2 ) \pm 0}{2 ( - 1 )}

x = \frac{- ( - 2 2 )}{2 ( - 1 )}

\frac{- ( - 2 2 )}{2 ( - 1 )} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

6 x^{2} - 4 x + 11 = 0

x^{2} = 5^{2} + 8^{2}

x, y^{2} + 4 x^{2} - 2 x y + 3 x - 2 y - 12 = 0

y^{2} = 19 y

30 x^{2} + 10 = 50

What are the solutions to the equation -x^2-sqrt(2)x-2=sqrt(2)x ?
The solutions to the equation -x^2-sqrt(2)x-2=sqrt(2)x are x=-sqrt(2)
Find the zeros of -x^2-sqrt(2)x-2=sqrt(2)x
The zeros of -x^2-sqrt(2)x-2=sqrt(2)x are x=-sqrt(2)