What are the solutions to the equation 30x^2+10=50 ?

The solutions to the equation 30x^2+10=50 are x= 2/(sqrt(3)),x=-2/(sqrt(3))

Find the zeros of 30x^2+10=50

The zeros of 30x^2+10=50 are x= 2/(sqrt(3)),x=-2/(sqrt(3))

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30 x^{2} + 10 = 50

x = \frac{2}{3}, x = - \frac{2}{3}

Decimal Notation

x = 1.15470 \dots, x = - 1.15470 \dots

Solution steps

30 x^{2} + 10 = 50

Move

10

to the right side

30 x^{2} = 40

Divide both sides by

30

x^{2} = \frac{4}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{4}{3}, x = - \frac{4}{3}

\frac{4}{3} = \frac{2}{3}

- \frac{4}{3} = - \frac{2}{3}

x = \frac{2}{3}, x = - \frac{2}{3}

(x - 1) (x + 2) = 18

x, (x - t)^{2} + (y + 2 t)^{2} = 169

3 (n + 1)^{2} - 7 = 20

16 z^{2} = 25

x, 5 x^{2} + 2 x y + 10 y^{2} - 12 x - 22 y + 17 = 0

What are the solutions to the equation 30x^2+10=50 ?
The solutions to the equation 30x^2+10=50 are x= 2/(sqrt(3)),x=-2/(sqrt(3))
Find the zeros of 30x^2+10=50
The zeros of 30x^2+10=50 are x= 2/(sqrt(3)),x=-2/(sqrt(3))