What are the solutions to the equation 3(n+1)^2-7=20 ?

The solutions to the equation 3(n+1)^2-7=20 are n=2,n=-4

Find the zeros of 3(n+1)^2-7=20

The zeros of 3(n+1)^2-7=20 are n=2,n=-4

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3 (n + 1)^{2} - 7 = 20

n = 2, n = - 4

Solution steps

3 (n + 1)^{2} - 7 = 20

Move

7

to the right side

3 (n + 1)^{2} = 27

Divide both sides by

3

(n + 1)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

n + 1 = 9 : n = 2

Solve

n + 1 = - 9 : n = - 4

The solutions to the quadratic equation are:

n = 2, n = - 4

16 z^{2} = 25

x, 5 x^{2} + 2 x y + 10 y^{2} - 12 x - 22 y + 17 = 0

- \frac{x ^{2}}{4} - \frac{4 x}{3} + 7 = 0

3 x^{2} - 16 x - 5 = 0

x^{2} + 22 x + 121 = 0

What are the solutions to the equation 3(n+1)^2-7=20 ?
The solutions to the equation 3(n+1)^2-7=20 are n=2,n=-4
Find the zeros of 3(n+1)^2-7=20
The zeros of 3(n+1)^2-7=20 are n=2,n=-4