What are the solutions to the equation x^2+8x+16=-64 ?

The solutions to the equation x^2+8x+16=-64 are x=-4+8i,x=-4-8i

Find the zeros of x^2+8x+16=-64

The zeros of x^2+8x+16=-64 are x=-4+8i,x=-4-8i

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x^{2} + 8 x + 16 = - 64

x = - 4 + 8 i, x = - 4 - 8 i

Solution steps

x^{2} + 8 x + 16 = - 64

Move

64

to the left side

x^{2} + 8 x + 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 80}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 80 : 16 i

x_{1, 2} = \frac{- 8 \pm 16 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 16 i}{2 \cdot 1}, x_{2} = \frac{- 8 - 16 i}{2 \cdot 1}

x = \frac{- 8 + 16 i}{2 \cdot 1} : - 4 + 8 i

x = \frac{- 8 - 16 i}{2 \cdot 1} : - 4 - 8 i

The solutions to the quadratic equation are:

x = - 4 + 8 i, x = - 4 - 8 i

(x + 3)^{2} + x^{2} = 269

Y^{2} + 4 Y = 0

(x - 2)^{2} = (2 x - 3)^{2} - 1

3 x^{2} - 18 x - 21 = 0

8 0^{2} + 6 0^{2} = x^{2}

What are the solutions to the equation x^2+8x+16=-64 ?
The solutions to the equation x^2+8x+16=-64 are x=-4+8i,x=-4-8i
Find the zeros of x^2+8x+16=-64
The zeros of x^2+8x+16=-64 are x=-4+8i,x=-4-8i