What are the solutions to the equation Y^2+4Y=0 ?

The solutions to the equation Y^2+4Y=0 are Y=0,Y=-4

Find the zeros of Y^2+4Y=0

The zeros of Y^2+4Y=0 are Y=0,Y=-4

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Y^{2} + 4 Y = 0

Y = 0, Y = - 4

Solution steps

Y^{2} + 4 Y = 0

Solve with the quadratic formula

Y_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 0 = 4

Y_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 1}

Separate the solutions

Y_{1} = \frac{- 4 + 4}{2 \cdot 1}, Y_{2} = \frac{- 4 - 4}{2 \cdot 1}

Y = \frac{- 4 + 4}{2 \cdot 1} : 0

Y = \frac{- 4 - 4}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

Y = 0, Y = - 4

(x - 2)^{2} = (2 x - 3)^{2} - 1

3 x^{2} - 18 x - 21 = 0

8 0^{2} + 6 0^{2} = x^{2}

x, x^{2} + 6 x = - 5

c (x) = 5 x^{2} - 1000 x + 62500

What are the solutions to the equation Y^2+4Y=0 ?
The solutions to the equation Y^2+4Y=0 are Y=0,Y=-4
Find the zeros of Y^2+4Y=0
The zeros of Y^2+4Y=0 are Y=0,Y=-4