What are the solutions to the equation solvefor x,x^2+6x=-5 ?

The solutions to the equation solvefor x,x^2+6x=-5 are x=-1,x=-5

Find the zeros of solvefor x,x^2+6x=-5

The zeros of solvefor x,x^2+6x=-5 are x=-1,x=-5

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x, x^{2} + 6 x = - 5

x = - 1, x = - 5

Solution steps

x^{2} + 6 x = - 5

Move

5

to the left side

x^{2} + 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 5 = 4

x_{1, 2} = \frac{- 6 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 4}{2 \cdot 1}, x_{2} = \frac{- 6 - 4}{2 \cdot 1}

x = \frac{- 6 + 4}{2 \cdot 1} : - 1

x = \frac{- 6 - 4}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = - 1, x = - 5

c (x) = 5 x^{2} - 1000 x + 62500

y^{2} - 7 y - 30 = 0

v, m E = \frac{1}{2} m v^{2} + m g h

54 x^{2} - 17 x = 96

13 r^{2} + 52 r + 21 = 0

What are the solutions to the equation solvefor x,x^2+6x=-5 ?
The solutions to the equation solvefor x,x^2+6x=-5 are x=-1,x=-5
Find the zeros of solvefor x,x^2+6x=-5
The zeros of solvefor x,x^2+6x=-5 are x=-1,x=-5