What are the solutions to the equation 54x^2-17x=96 ?

The solutions to the equation 54x^2-17x=96 are x= 3/2 ,x=-32/27

Find the zeros of 54x^2-17x=96

The zeros of 54x^2-17x=96 are x= 3/2 ,x=-32/27

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54 x^{2} - 17 x = 96

x = \frac{3}{2}, x = - \frac{32}{27}

Decimal Notation

x = 1.5, x = - 1.18518 \dots

Solution steps

54 x^{2} - 17 x = 96

Move

96

to the left side

54 x^{2} - 17 x - 96 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 54 ( - 96 )}{2 \cdot 54}

(- 17)^{2} - 4 \cdot 54 (- 96) = 145

x_{1, 2} = \frac{- ( - 17 ) \pm 145}{2 \cdot 54}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 145}{2 \cdot 54}, x_{2} = \frac{- ( - 17 ) - 145}{2 \cdot 54}

x = \frac{- ( - 17 ) + 145}{2 \cdot 54} : \frac{3}{2}

x = \frac{- ( - 17 ) - 145}{2 \cdot 54} : - \frac{32}{27}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - \frac{32}{27}

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1 5^{2} = x^{2} + 9^{2}

2 x^{2} + (m - 2) x + 3 = m - 3 x

x, (x - 6)^{2} + (y - 8)^{2} = k

What are the solutions to the equation 54x^2-17x=96 ?
The solutions to the equation 54x^2-17x=96 are x= 3/2 ,x=-32/27
Find the zeros of 54x^2-17x=96
The zeros of 54x^2-17x=96 are x= 3/2 ,x=-32/27