What are the solutions to the equation 4x^2+28x-72=0 ?

The solutions to the equation 4x^2+28x-72=0 are x=2,x=-9

Find the zeros of 4x^2+28x-72=0

The zeros of 4x^2+28x-72=0 are x=2,x=-9

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4 x^{2} + 28 x - 72 = 0

x = 2, x = - 9

Solution steps

4 x^{2} + 28 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 4 ( - 72 )}{2 \cdot 4}

2 8^{2} - 4 \cdot 4 (- 72) = 44

x_{1, 2} = \frac{- 28 \pm 44}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 28 + 44}{2 \cdot 4}, x_{2} = \frac{- 28 - 44}{2 \cdot 4}

x = \frac{- 28 + 44}{2 \cdot 4} : 2

x = \frac{- 28 - 44}{2 \cdot 4} : - 9

The solutions to the quadratic equation are:

x = 2, x = - 9

x^{2} - 6 x - 9 = 0

x^{2} + 4 k x + (3 + 11 k)

(x - 2)^{2} - 7 = 5

6 x^{2} + (4 n - 3 m) x - 2 mn = 0

12 k^{2} - 19 k + 4 = 0

What are the solutions to the equation 4x^2+28x-72=0 ?
The solutions to the equation 4x^2+28x-72=0 are x=2,x=-9
Find the zeros of 4x^2+28x-72=0
The zeros of 4x^2+28x-72=0 are x=2,x=-9