What are the solutions to the equation m^2+4m+4=0 ?

The solutions to the equation m^2+4m+4=0 are m=-2

Find the zeros of m^2+4m+4=0

The zeros of m^2+4m+4=0 are m=-2

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m^{2} + 4 m + 4 = 0

m = - 2

Solution steps

m^{2} + 4 m + 4 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

m_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

m = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

m = - 2

The solution to the quadratic equation is:

m = - 2

7175 + 7

x^{2} - 2 x - 8 = 0

x^{4} + 10 x^{2} + 9

a^{2} - a - 2

(\frac{27 t ^{3}}{8})^{\frac{2}{3}}

What are the solutions to the equation m^2+4m+4=0 ?
The solutions to the equation m^2+4m+4=0 are m=-2
Find the zeros of m^2+4m+4=0
The zeros of m^2+4m+4=0 are m=-2