What are the solutions to the equation x^2-2x-8=0 ?

The solutions to the equation x^2-2x-8=0 are x=4,x=-2

Find the zeros of x^2-2x-8=0

The zeros of x^2-2x-8=0 are x=4,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 2 x - 8 = 0

x = 4, x = - 2

Solution steps

x^{2} - 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 8) = 6

x_{1, 2} = \frac{- ( - 2 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 6}{2 \cdot 1}

x = \frac{- ( - 2 ) + 6}{2 \cdot 1} : 4

x = \frac{- ( - 2 ) - 6}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 4, x = - 2

x^{4} + 10 x^{2} + 9

a^{2} - a - 2

(\frac{27 t ^{3}}{8})^{\frac{2}{3}}

- 3 x + 2 \leq x < 2 x + 5

3 x^{2} + 3 x - 18 = 0

What are the solutions to the equation x^2-2x-8=0 ?
The solutions to the equation x^2-2x-8=0 are x=4,x=-2
Find the zeros of x^2-2x-8=0
The zeros of x^2-2x-8=0 are x=4,x=-2