What are the solutions to the equation 3x^2+3x-18=0 ?

The solutions to the equation 3x^2+3x-18=0 are x=2,x=-3

Find the zeros of 3x^2+3x-18=0

The zeros of 3x^2+3x-18=0 are x=2,x=-3

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3 x^{2} + 3 x - 18 = 0

x = 2, x = - 3

Solution steps

3 x^{2} + 3 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 3 ( - 18 )}{2 \cdot 3}

3^{2} - 4 \cdot 3 (- 18) = 15

x_{1, 2} = \frac{- 3 \pm 15}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 3 + 15}{2 \cdot 3}, x_{2} = \frac{- 3 - 15}{2 \cdot 3}

x = \frac{- 3 + 15}{2 \cdot 3} : 2

x = \frac{- 3 - 15}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

x = 2, x = - 3

\frac{60}{169} + \frac{12}{25}

3 d + 1 > 10

c^{2} + 2 c = 0

\frac{16 !}{( 16 - 3 ) ! 3 !}

- 5 y + 2 (2 y + 1) = 2 (5 y - 1) - 7

What are the solutions to the equation 3x^2+3x-18=0 ?
The solutions to the equation 3x^2+3x-18=0 are x=2,x=-3
Find the zeros of 3x^2+3x-18=0
The zeros of 3x^2+3x-18=0 are x=2,x=-3