What are the solutions to the equation 5s^2-s+1=0 ?

The solutions to the equation 5s^2-s+1=0 are s= 1/10+i(sqrt(19))/(10),s= 1/10-i(sqrt(19))/(10)

Find the zeros of 5s^2-s+1=0

The zeros of 5s^2-s+1=0 are s= 1/10+i(sqrt(19))/(10),s= 1/10-i(sqrt(19))/(10)

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5 s^{2} - s + 1 = 0

s = \frac{1}{10} + i \frac{19}{10}, s = \frac{1}{10} - i \frac{19}{10}

Solution steps

5 s^{2} - s + 1 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 5 \cdot 1}{2 \cdot 5}

Simplify

(- 1)^{2} - 4 \cdot 5 \cdot 1 : 19 i

s_{1, 2} = \frac{- ( - 1 ) \pm 19 i}{2 \cdot 5}

Separate the solutions

s_{1} = \frac{- ( - 1 ) + 19 i}{2 \cdot 5}, s_{2} = \frac{- ( - 1 ) - 19 i}{2 \cdot 5}

s = \frac{- ( - 1 ) + 19 i}{2 \cdot 5} : \frac{1}{10} + i \frac{19}{10}

s = \frac{- ( - 1 ) - 19 i}{2 \cdot 5} : \frac{1}{10} - i \frac{19}{10}

The solutions to the quadratic equation are:

s = \frac{1}{10} + i \frac{19}{10}, s = \frac{1}{10} - i \frac{19}{10}

- 2 x^{2} + x = 6

x, y = I n (x^{2} + 3)

4 x^{2} + 9 x + 3 = 0

X, X^{2} + Y^{2} = 0

- 6 x (x - 1) = 0

What are the solutions to the equation 5s^2-s+1=0 ?
The solutions to the equation 5s^2-s+1=0 are s= 1/10+i(sqrt(19))/(10),s= 1/10-i(sqrt(19))/(10)
Find the zeros of 5s^2-s+1=0
The zeros of 5s^2-s+1=0 are s= 1/10+i(sqrt(19))/(10),s= 1/10-i(sqrt(19))/(10)