What are the solutions to the equation 6p^2-10=-57 ?

The solutions to the equation 6p^2-10=-57 are p=sqrt(47/6)i,p=-sqrt(47/6)i

Find the zeros of 6p^2-10=-57

The zeros of 6p^2-10=-57 are p=sqrt(47/6)i,p=-sqrt(47/6)i

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6 p^{2} - 10 = - 57

p = \frac{47}{6} i, p = - \frac{47}{6} i

Solution steps

6 p^{2} - 10 = - 57

Move

10

to the right side

6 p^{2} = - 47

Divide both sides by

6

p^{2} = - \frac{47}{6}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = - \frac{47}{6}, p = - - \frac{47}{6}

- \frac{47}{6} = \frac{47}{6} i

- - \frac{47}{6} = - \frac{47}{6} i

p = \frac{47}{6} i, p = - \frac{47}{6} i

0 = - 20 x^{2} + 360 x + 1000

45 = \frac{1}{2} (5) v^{2}

a, a^{2} = b^{2} + c^{2} - 2 b c

2 a x^{2} + (2 a^{2} - a - 4) x - (2 + a^{2}) = 0

(x + 8)^{2} - 1 = 0

What are the solutions to the equation 6p^2-10=-57 ?
The solutions to the equation 6p^2-10=-57 are p=sqrt(47/6)i,p=-sqrt(47/6)i
Find the zeros of 6p^2-10=-57
The zeros of 6p^2-10=-57 are p=sqrt(47/6)i,p=-sqrt(47/6)i